Geometric Proof
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AQA Level 2 Further Maths practice questions, each with a hint and a full worked solution.
Have a pen and paper handy, to work out your answers.
Question 11 mark
A, B and C are points on a circle.
TA is a tangent to the circle at A.
Angle TAB=y
In a proof, a student writes
angle ACB=y
Which reason should the student give?
Hint
The angle y is between a tangent and a chord, and there are no parallel lines in the diagram.
Worked solution
- Angle TAB is between the tangent TA and the chord AB
- Angle ACB is in the segment on the other side of AB (the alternate segment)
- So they are equal by the alternate segment theorem
- 'Alternate angles' needs parallel lines, which there are not here
- Answer: Alternate segment theorem
Question 23 marks
A, B, C and D are points on a circle.
ABE is a straight line.
DA=DC
Angle CBE=x
Work out an expression for angle DAC in terms of x.
Give your answer in its simplest form.
Hint
Find angle ABC first, then use the fact that ABCD is a cyclic quadrilateral.
Worked solution
- Angle ABC=180^\circ-x (angles on a straight line add up to 180^\circ)
- Angle ADC=180^\circ-(180^\circ-x)=x (opposite angles of a cyclic quadrilateral add up to 180^\circ)
- Triangle ADC is isosceles because DA=DC, so angle DAC= angle DCA (base angles of an isosceles triangle are equal)
- Angle DAC=\dfrac{180^\circ-x}{2} (angles in a triangle add up to 180^\circ)
- Answer: 90^\circ-\dfrac{x}{2}
Question 3Challenge5 marks
A, B and C are points on a circle, centre O.
TA is a tangent to the circle at A.
Angle TAB=3x Angle OBA=2x+15^\circ
Work out the value of x.
3 marks
Angle OAC=20^\circ
Work out the size of angle ABC.
2 marks
Hint
Radii are equal, and a tangent is perpendicular to the radius at the point of contact.
Worked solution
Part (a)
- OA=OB (radii), so triangle OAB is isosceles
- Angle OAB= angle OBA=2x+15^\circ (base angles of an isosceles triangle are equal)
- Angle OAT=90^\circ (the angle between a tangent and a radius is 90^\circ)
- So (2x+15)+3x=90
- 5x=75
- Answer: x=15
Part (b)
- Angle TAB=3\times15=45^\circ and angle OAB=2\times15+15=45^\circ
- Angle ACB=45^\circ (alternate segment theorem)
- Angle CAB=20^\circ+45^\circ=65^\circ
- Angle ABC=180^\circ-65^\circ-45^\circ=70^\circ (angles in a triangle add up to 180^\circ)
- Answer: 70^\circ
More on this topic: Geometric Proof worksheet with full solutions
All AQA Level 2 Further Maths practice questions
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