Differentiation
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AQA Level 2 Further Maths practice questions, each with a hint and a full worked solution.
Have a pen and paper handy, to work out your answers.
Question 12 marks
y=(2x-5)(x^2+3)
Work out \dfrac{dy}{dx}
Hint
Expand the brackets first, then differentiate each term.
Worked solution
- Expand: y=2x^3+6x-5x^2-15
- Write in order: y=2x^3-5x^2+6x-15
- Differentiate each term: 6x^2-10x+6 (the -15 differentiates to 0)
- Answer: \dfrac{dy}{dx}=6x^2-10x+6
Question 23 marks
A curve has equation y=3x^4-5x+\dfrac{8}{x^2}
Work out the value of \dfrac{d^2y}{dx^2} when x=2
Hint
Write \dfrac{8}{x^2} as 8x^{-2}, differentiate twice, then substitute x=2
Worked solution
- Write as powers of x: y=3x^4-5x+8x^{-2}
- Differentiate: \dfrac{dy}{dx}=12x^3-5-16x^{-3}
- Differentiate again: \dfrac{d^2y}{dx^2}=36x^2+48x^{-4}
- Substitute x=2: 36\times4+\dfrac{48}{16}=144+3
- Answer: 147
Question 3Challenge5 marks
A curve has equation y=\dfrac{(x-4)^2}{2x}
Work out \dfrac{dy}{dx}
3 marks
Work out the x-coordinates of the two points on the curve where the rate of change of y with respect to x is -\dfrac{3}{2}
2 marks
Hint
Do not differentiate the top and bottom separately: expand and split the fraction into separate powers of x first.
Worked solution
Part (a)
- Expand the top: (x-4)^2=x^2-8x+16
- Divide each term by 2x: y=\dfrac{x}{2}-4+\dfrac{8}{x}
- Write as powers of x: y=\frac12x-4+8x^{-1}
- Differentiate: \frac12-8x^{-2}
- Answer: \dfrac{dy}{dx}=\dfrac12-\dfrac{8}{x^2}
Part (b)
- Rate of change of y with respect to x means \dfrac{dy}{dx}
- \dfrac12-\dfrac{8}{x^2}=-\dfrac32
- \dfrac{8}{x^2}=2, so x^2=4
- Answer: x=2 or x=-2
More on this topic: Differentiation worksheet with full solutions
All AQA Level 2 Further Maths practice questions
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