Binomial Expansion
This section is in development. More questions and features coming shortly.
AQA Level 2 Further Maths practice questions, each with a hint and a full worked solution.
Have a pen and paper handy, to work out your answers.
Question 11 mark
Which of these is the term in x^3 in the expansion of (1-3x)^4?
Hint
Use the row 1\;4\;6\;4\;1 of Pascal's triangle, and remember the whole term -3x is cubed.
Worked solution
- Row 4 of Pascal's triangle is 1\;4\;6\;4\;1
- The x^3 term uses the fourth number, 4, with 1^1 and (-3x)^3
- (-3x)^3=-27x^3 (cube the -3 as well as the x)
- 4\times 1\times(-27x^3)=-108x^3
- Answer: -108x^3
Question 23 marks
Expand and simplify fully (2+3x)^4
Hint
Use the row 1\;4\;6\;4\;1 of Pascal's triangle, with powers of 2 going down and powers of 3x going up.
Worked solution
- Row 4 of Pascal's triangle: 1\;4\;6\;4\;1
- 1\times2^4=16
- 4\times2^3\times(3x)=96x
- 6\times2^2\times(3x)^2=6\times4\times9x^2=216x^2
- 4\times2\times(3x)^3=4\times2\times27x^3=216x^3
- 1\times(3x)^4=81x^4
- Answer: 16+96x+216x^2+216x^3+81x^4
Question 3Challenge5 marks
a is a negative constant.
In the expansion of (2+ax)^4 the coefficient of x^2 is 600
Work out the value of a.
2 marks
Work out the coefficient of x^2 in the expansion of (1+3x)(2+ax)^4
3 marks
Hint
Square the whole term ax when you find the x^2 coefficient; for part (b) you need the x term of (2+ax)^4 as well as the x^2 term.
Worked solution
Part (a)
- The x^2 term is 6\times2^2\times(ax)^2
- (ax)^2=a^2x^2, so the coefficient is 24a^2
- 24a^2=600
- a^2=25, so a=5 or a=-5
- a is negative, so a=-5
Part (b)
- With a=-5: (2-5x)^4
- Constant term: 2^4=16 (not needed)
- x term: 4\times2^3\times(-5x)=-160x
- x^2 term: 600x^2 (from part a)
- In (1+3x)(\dots) the x^2 terms come from 1\times600x^2 and 3x\times(-160x)
- 600-480=120
- Answer: 120
More on this topic: Binomial Expansion worksheet with full solutions
All AQA Level 2 Further Maths practice questions
Unofficial practice questions written by Teach Me Maths. Not produced or endorsed by AQA.