Spheres, Cones and Pyramids
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How to name pyramids, cones and spheres, count the faces and edges of a pyramid, sketch its plan and front elevation, and work out the surface area of a pyramid and of a sphere.
Spheres, cones and pyramids in the exam
Questions on these solids are short and do not come up often. You may be shown a solid, such as a cone, and asked to write down its name. You may be asked to count the faces or edges of a pyramid, or to draw the plan or front elevation of a pyramid. These are worth 1 or 2 marks each.
The longer questions, for about 4 marks, ask for a surface area: the total area of the faces of a pyramid, or the surface area of a sphere.
For a sphere, the formula you need is printed in the question: "Surface area of sphere = 4\pi r^2". It is not on the formulae sheet. Your job is to know what r stands for and to put the right number in. For a pyramid there is no formula: you add up the areas of the square and the triangles, so learn the area of a square and of a triangle.
On Paper 1, with no calculator, leave \pi in a sphere's surface area, such as 64\pi\text{ cm}^2. With a calculator, use the \pi key and round only at the end.
Pyramids, cones and spheres
A pyramid has a flat base and triangular faces that slope up to a point at the top. A square-based pyramid has a square base and four triangles.
A cone has a circular base and a curved surface that rises to a point. A sphere is a ball shape: every point on its surface is the same distance from the centre. That distance is the radius, r.
Learn the three names. A question may show a solid, such as a cone, and ask you to write down its name, for 1 mark.
Give one name, the name of a solid. A cone is a "cone", not a "triangle cone" or a "cylinder cone". A sphere is a solid, so it is not a circle.
Faces and edges
A face is a flat surface of a solid. An edge is a line where two faces meet. The corners, where edges meet, are called vertices.
A square-based pyramid has 5 faces: the square base and 4 triangles. It has 8 edges: 4 round the base and 4 that slope up to the top.
In a drawing, the edges you cannot see are drawn dashed. Count them too. Go round the base first, then count the edges that go up to the top.
Worked example 1: Counting faces and edges
The diagram shows a solid pyramid with a triangle for its base.
(a) Write down the number of faces of the pyramid.
(b) Write down the number of edges of the pyramid.
- The base is a triangle. One edge at the back of the base cannot be seen, so it is drawn dashed.
- (a) Faces: the triangle at the base and 3 triangles that slope up to the top, so 1 + 3 = 4 faces.
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Your turn. (b) Count the edges round the base, then the edges that go up to the top. How many edges are there altogether?
3 round the base and 3 up to the top: 3 + 3 = 6 edges, one of them dashed
- Answer: (a) 4 (b) 6
The plan and front elevation of a pyramid
The plan is the view of a solid from above. The front elevation is the view from the front. Each one is a flat 2-D shape: not a 3-D drawing, and not the faces laid out together.
Here are the plan and front elevation of a square-based pyramid.
From above, the four sloping edges run from the corners of the square to the top, which is over the middle. So the plan is a square with both diagonals drawn. A square on its own is only half right.
From the front you see a triangle. Its base is the side of the square. Its height is the vertical height of the pyramid: the height straight up from the middle of the base to the top, not the length up a sloping face.
Worked example 2: Sketching the plan and front elevation
A tent is in the shape of a square-based pyramid. The floor of the tent is a square of side 3 m. The top of the tent is 2 m above the middle of the floor.
Draw a sketch of the plan and a sketch of the front elevation of the tent. Mark the lengths on your sketches.
- The plan is the view from above. The floor is a square, 3 m by 3 m.
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Your turn. From above, each sloping edge runs from a corner of the floor to the point over the middle. How many lines meet at the middle of the plan?
4 lines meet at the middle. They make the two diagonals of the square.
- The front elevation is a triangle. Its base is the side of the floor, 3 m. Its height is the height of the tent, 2 m, not the length of a sloping side.
- Here are the two sketches, with the lengths marked.
- Answer: the plan is a square of side 3 m with both diagonals, and the front elevation is a triangle with base 3 m and height 2 m.
The surface area of a pyramid
The surface area of a solid is the total area of all its outside surfaces. It is measured in square units, such as \text{cm}^2
For a pyramid, add up the areas of its faces. A square-based pyramid has a square base and four identical triangles.
Each triangle has area \frac{1}{2} \times 8 \times 11 = 44\text{ cm}^2, so the four triangles make 4 \times 44 = 176\text{ cm}^2. Add the square base, 8 \times 8 = 64\text{ cm}^2. The total surface area is 176 + 64 = 240\text{ cm}^2
The height of each triangle is measured up the middle of its sloping face. It is longer than the vertical height of the pyramid. Use the height of the triangle for the surface area. The vertical height is for the front elevation.
Worked example 3: The surface area of a pyramid
A wooden block is a solid square-based pyramid. The base is a square of side 16 cm. The vertical height of the block is 6 cm. Each triangular face has a height of 10 cm.
Work out the total surface area of the block.
- The block has 5 faces: the square base and 4 identical triangles.
- Each triangle has a base of 16 cm and a height of 10 cm. The vertical height, 6 cm, is not used.
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Your turn. Work out the area of one triangular face, in \text{cm}^2
\frac{1}{2} \times 16 \times 10 = 80\text{ cm}^2
- Four triangles: 4 \times 80 = 320\text{ cm}^2. The base: 16 \times 16 = 256\text{ cm}^2
- Total: 320 + 256 = 576
- Answer: 576\text{ cm}^2
The surface area of a sphere
The formula is printed in the question:
\text{Surface area of sphere} = 4\pi r^2
where r is the radius of the sphere.
4\pi r^2 means 4 \times \pi \times r \times r. Square the radius first, then multiply by 4. A sphere of radius 2 cm has surface area 4 \times \pi \times 2^2 = 4 \times 4 \times \pi = 16\pi\text{ cm}^2
The formula uses the radius. If you are given the diameter, halve it first.
If the question says "in terms of \pi", leave \pi in the answer, such as 16\pi. Do not put in 3.14. If you can use a calculator and the answer is to be rounded, use the \pi key and round only at the end.
Worked example 4: The surface area of a sphere in terms of π
A small globe is a sphere with radius 7 cm.
Surface area of sphere = 4\pi r^2
Work out the surface area of the globe. Give your answer in terms of \pi
- r = 7, so the surface area is 4 \times \pi \times 7^2
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Your turn. Square the radius first, then multiply by 4. Work out the surface area, in terms of \pi. You can type pi.
7^2 = 49 and 4 \times 49 = 196, so the surface area is 196\pi
- Answer: 196\pi\text{ cm}^2
Worked example 5: Painting a sphere
A sculpture in a park is a sphere with a diameter of 2.4 m. The outside of the sculpture is going to be painted.
Surface area of sphere = 4\pi r^2
One tin of paint covers 5\text{ m}^2
Work out the least number of tins of paint needed.
- The formula uses the radius. The diameter is 2.4 m, so the radius is 2.4 \div 2 = 1.2 m.
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Your turn. Work out the surface area of the sculpture, in \text{m}^2. Give your answer correct to 1 decimal place.
4 \times \pi \times 1.2^2 = 5.76\pi = 18.095\ldots, which is 18.1\text{ m}^2 correct to 1 decimal place.
- Use the unrounded area. Number of tins: 18.095\ldots \div 5 = 3.619\ldots
- 3 tins cover only 3 \times 5 = 15\text{ m}^2, which is not enough. So round up to 4 tins.
- Answer: 4 tins
Common mistakes
- Giving two names, or the name of a flat shape. Write one name of a solid: "cone", not "triangle cone"; a sphere is not a circle.
- Not counting the hidden edges. Count the dashed edges as well as the ones you can see.
- Drawing a 3-D picture for a plan or elevation. Draw a flat shape. The plan of a square-based pyramid is a square with both diagonals.
- Using the vertical height for the triangular faces. Each triangle's area uses the height of the triangle, measured up the sloping face.
- Using the diameter instead of the radius. Halve the diameter before you put it into 4\pi r^2
- Putting in a number for \pi when the answer must be in terms of \pi. Keep \pi in the answer, such as 196\pi
More on this topic: Spheres, Cones and Pyramids worksheet with full solutions