Sampling - Estimating a Population
Question 11 mark
Nadia and Owen want to find out if a coin is biased.
Nadia throws the coin 20 times. She gets 12 heads.
Owen throws the same coin 200 times. He gets 94 heads.
Whose results are more reliable? Choose the answer with the correct reason.
Hint
More throws give more reliable results.
Worked solution
Nadia and Owen want to find out if a coin is biased.
Nadia throws the coin 20 times. She gets 12 heads.
Owen throws the same coin 200 times. He gets 94 heads.
Whose results are more reliable? Choose the answer with the correct reason.
- Nadia's, because she got a greater proportion of heads
- Owen's, because he threw the coin more times than Nadia
- Nadia's, because fewer throws are easier to count
- Owen's, because he got more heads than Nadia
- Results from more throws are more reliable: a few unusual throws make less difference.
- Owen threw the coin 200 times and Nadia only 20 times, so Owen's results are more reliable.
- Getting more heads is not a reason: Owen got more heads only because he threw the coin more times.
Question 22 marks
A factory makes 600 mugs one day.
A manager checks a sample of 30 of these mugs.
2 of the mugs in the sample are cracked.
Work out an estimate for the number of cracked mugs made that day.
Hint
How many times bigger is 600 than 30?
Worked solution
A factory makes 600 mugs one day.
A manager checks a sample of 30 of these mugs.
2 of the mugs in the sample are cracked.
Work out an estimate for the number of cracked mugs made that day.
- 600\div30=20, so each mug in the sample stands for 20 mugs.
- 2\times20=40 cracked mugs.
Question 31 mark
Lily asks a sample of 50 of the 1000 people at a music festival which food stall they will use.
She uses her results to work out an estimate for the number of people at the festival who will use the pizza stall.
Which of these is an assumption Lily has made?
Hint
An assumption is something Lily takes to be true when she uses her sample for everyone.
Worked solution
Lily asks a sample of 50 of the 1000 people at a music festival which food stall they will use.
She uses her results to work out an estimate for the number of people at the festival who will use the pizza stall.
Which of these is an assumption Lily has made?
- She divided 1000 by 50 to get 20
- The sample of 50 people is too small
- The 50 people she asked are representative of all 1000 people at the festival
- Pizza is the most popular food at the festival
- Lily uses the results of 50 people for all 1000 people.
- So she assumes the people she asked are representative: the others would answer in the same way.
- Describing the working, or saying the sample is too small, is not an assumption.
Question 41 mark
Hari asks 20 people which sport they like best. 6 of them choose rugby.
Cara asks 60 people which sport they like best. 12 of them choose rugby.
Which statement is correct?
Hint
Write each result as a fraction or a percentage of the people asked.
Worked solution
Hari asks 20 people which sport they like best. 6 of them choose rugby.
Cara asks 60 people which sport they like best. 12 of them choose rugby.
Which statement is correct?
- A greater proportion of people chose rugby in Hari's survey
- A greater proportion of people chose rugby in Cara's survey
- The same proportion of people chose rugby in both surveys
- You cannot compare surveys that asked different numbers of people
- Hari: \frac{6}{20}=30\% chose rugby.
- Cara: \frac{12}{60}=20\% chose rugby.
- So a greater proportion chose rugby in Hari's survey, even though more people chose rugby in Cara's.
Question 51 mark
Kai and Lena each throw the same dice to see if it is biased.
Kai throws the dice 10 times. He gets a six 4 times.
Lena throws the dice 40 times. She gets a six 14 times.
Use all of these results to work out an estimate for the probability of getting a six with this dice. Give your answer as a fraction or a decimal.
Hint
Add the numbers of sixes, and add the numbers of throws.
Worked solution
Kai and Lena each throw the same dice to see if it is biased.
Kai throws the dice 10 times. He gets a six 4 times.
Lena throws the dice 40 times. She gets a six 14 times.
Use all of these results to work out an estimate for the probability of getting a six with this dice. Give your answer as a fraction or a decimal.
- Sixes: 4+14=18
- Throws: 10+40=50
- Estimate for the probability =\frac{18}{50}=0.36
Question 62 marks
A café asks a sample of 25 customers which cake they would choose.
9 choose lemon, 11 choose chocolate and 5 choose carrot.
The café expects to sell 400 cakes next week.
Work out how many lemon cakes the café should make.
Hint
Find the fraction of the sample who choose lemon, then find that fraction of 400.
Worked solution
A café asks a sample of 25 customers which cake they would choose.
9 choose lemon, 11 choose chocolate and 5 choose carrot.
The café expects to sell 400 cakes next week.
Work out how many lemon cakes the café should make.
- \frac{9}{25} of the sample choose lemon.
- 400\div25=16, so each customer in the sample stands for 16 cakes.
- 9\times16=144 lemon cakes.
Question 72 marks
Asha asks 40 of the 720 students at a college whether they have a part-time job.
13 of the students she asks have a part-time job.
Work out an estimate for the number of the 720 students who do not have a part-time job.
Hint
First work out how many students in the sample do not have a part-time job.
Worked solution
Asha asks 40 of the 720 students at a college whether they have a part-time job.
13 of the students she asks have a part-time job.
Work out an estimate for the number of the 720 students who do not have a part-time job.
- In the sample, 40-13=27 students do not have a part-time job.
- 720\div40=18
- 27\times18=486 students.
Question 81 mark
In a random sample of 40 households, 14 have a dog. What percentage of the households in the sample have a dog?
Hint
Write the number with a dog as a fraction of the number of households in the sample.
Worked solution
In a random sample of 40 households, 14 have a dog. What percentage of the households in the sample have a dog?
- Fraction of the sample with a dog =14/40.
- Percentage =14÷40×100=35\%.
Question 91 mark
A sports club has 630 members.
In a sample of 45 members, 12 want a new club kit.
Which calculation gives an estimate for the number of the 630 members who want a new club kit?
Hint
Find the fraction of the sample who want a new kit, then find that fraction of all the members.
Worked solution
A sports club has 630 members.
In a sample of 45 members, 12 want a new club kit.
Which calculation gives an estimate for the number of the 630 members who want a new club kit?
- \frac{45}{12}\times630
- 630-45+12
- \frac{12}{45}\times630
- \frac{12}{630}\times45
- \frac{12}{45} of the sample want a new kit.
- So the estimate is \frac{12}{45}\times630=168 members.
- \frac{45}{12}\times630 gives more than 630, which cannot be right.
Question 101 mark
Two clubs each draw a pie chart to show their members' favourite sport.
In Club A's pie chart, the angle for tennis is 100^\circ.
In Club B's pie chart, the angle for tennis is 80^\circ.
Ola says, "More members of Club A chose tennis than members of Club B."
Is Ola right?
Hint
Does a pie chart tell you how many people were asked?
Worked solution
Two clubs each draw a pie chart to show their members' favourite sport.
In Club A's pie chart, the angle for tennis is 100^\circ.
In Club B's pie chart, the angle for tennis is 80^\circ.
Ola says, "More members of Club A chose tennis than members of Club B."
Is Ola right?
- Yes, because 100^\circ is bigger than 80^\circ
- No, because Club B's angle for tennis is smaller
- Not necessarily: a pie chart shows proportions, not numbers, and we do not know how many members each club has
- Yes, because a pie chart always shows the number of people
- The whole of each pie chart stands for all the members of that club.
- The angles show what proportion chose tennis, not how many people.
- If Club B has many more members, more of them could have chosen tennis, so Ola could be wrong.
Question 112 marks
Mia asks 50 people which fruit they like best. 19 of them choose apples.
Jack asks 90 people which fruit they like best. He draws a pie chart of his results. The angle for apples is 108^\circ.
What fraction of the people in Jack's survey chose apples? Give your answer in its simplest form.
1 mark
In whose survey did a greater proportion of people choose apples?
1 mark
Hint
Compare proportions, not numbers of people.
Worked solution
Mia asks 50 people which fruit they like best. 19 of them choose apples.
Jack asks 90 people which fruit they like best. He draws a pie chart of his results. The angle for apples is 108^\circ.
Part (a)
What fraction of the people in Jack's survey chose apples? Give your answer in its simplest form.
- \frac{108}{360}=\frac{3}{10}
Part (b)
In whose survey did a greater proportion of people choose apples?
- Mia's
- Jack's
- The proportion is the same in both surveys
- Mia: \frac{19}{50}=\frac{38}{100}=38\%
- Jack: \frac{3}{10}=30\% (and \frac{3}{10}\times90=27 people).
- 38\% is greater, so a greater proportion chose apples in Mia's survey, even though more people chose apples in Jack's.
Question 122 marks
A random sample of 60 members chooses an activity. The club has 450 members. Use the sample to estimate how many members would choose walking.
Hint
Use the sample proportion for walking.
Worked solution
A random sample of 60 members chooses an activity. The club has 450 members. Use the sample to estimate how many members would choose walking.
- Walking proportion =24/60=0.4.
- Estimated number =0.4×450=180 members. This assumes the sample represents the club.
Question 132 marks
Hana spins a spinner 10 times. It lands on red 7 times.
Ian spins the same spinner 90 times. It lands on red 45 times.
Gus says, "Hana's results give 0.7 and Ian's give 0.5, so the best estimate for the probability of red is the mean of these, 0.6"
Use all of the results to work out a better estimate for the probability that the spinner lands on red. Give your answer as a decimal.
1 mark
Why is Gus wrong?
1 mark
Hint
Add the counts and add the totals.
Worked solution
Hana spins a spinner 10 times. It lands on red 7 times.
Ian spins the same spinner 90 times. It lands on red 45 times.
Gus says, "Hana's results give 0.7 and Ian's give 0.5, so the best estimate for the probability of red is the mean of these, 0.6"
Part (a)
Use all of the results to work out a better estimate for the probability that the spinner lands on red. Give your answer as a decimal.
- Reds: 7+45=52
- Spins: 10+90=100
- Estimate =\frac{52}{100}=0.52
Part (b)
Why is Gus wrong?
- Ian spun the spinner more times, so his results should count for more than Hana's
- The mean of two probabilities is always more than 1
- Hana's results should count for more, because she got more reds
- Probabilities can never be added together
- Taking the mean counts Hana's 10 spins the same as Ian's 90 spins.
- Ian's results come from more spins, so they should count for more. Adding the counts and the totals does this.
Question 143 marks
Two random samples are used to estimate support for a new sports centre. Sample A has 24 supporters out of 40 people. Sample B has 33 supporters out of 60 people.
What percentage of sample A supports the centre?
1 mark
What percentage of sample B supports the centre?
1 mark
Which sample has the greater proportion of supporters?
1 mark
Hint
Convert both results to the same kind of measure.
Worked solution
Two random samples are used to estimate support for a new sports centre. Sample A has 24 supporters out of 40 people. Sample B has 33 supporters out of 60 people.
Part (a)
What percentage of sample A supports the centre?
- 24÷40×100=60\%.
Part (b)
What percentage of sample B supports the centre?
- 33÷60×100=55\%.
Part (c)
Which sample has the greater proportion of supporters?
- A
- B
- They are equal
- A has 60% support compared with B’s 55%. B has more supporters counted, but a lower proportion.
Question 153 marks
In a sample of 50 customers, 18 prefer a morning delivery. The business has 600 customers.
Estimate how many customers prefer a morning delivery.
2 marks
Which assumption supports this estimate?
1 mark
Hint
Link the calculation to its sampling assumption.
Worked solution
In a sample of 50 customers, 18 prefer a morning delivery. The business has 600 customers.
Part (a)
Estimate how many customers prefer a morning delivery.
- 18/50×600=216 customers.
Part (b)
Which assumption supports this estimate?
- The sample’s preferences are representative of all customers
- Every customer must prefer mornings
- The sample contains 600 customers
- The estimate assumes the sample has similar preferences to the full customer population. If it does not, the estimate may be too high or too low.
Question 16Challenge3 marks
A sports centre expects 2400 people at a swimming gala.
The manager asks a sample of 80 of these people what they will buy at the café.
30 say a hot drink, 18 say a cold drink and 32 say they will not buy a drink.
Work out an estimate for how many more of the 2400 people will buy a hot drink than a cold drink.
2 marks
Which of these is an assumption the manager makes, with how it could affect the answer to part (a)?
1 mark
Hint
Scale the sample up, then say what you assumed.
Worked solution
A sports centre expects 2400 people at a swimming gala.
The manager asks a sample of 80 of these people what they will buy at the café.
30 say a hot drink, 18 say a cold drink and 32 say they will not buy a drink.
Part (a)
Work out an estimate for how many more of the 2400 people will buy a hot drink than a cold drink.
- In the sample, 30-18=12 more chose a hot drink.
- 2400\div80=30
- 12\times30=360
Part (b)
Which of these is an assumption the manager makes, with how it could affect the answer to part (a)?
- The sample is too small, so the answer to part (a) must be too low
- The 80 people asked are representative of all the people at the gala; if they are not, the answer to part (a) could be too high or too low
- The manager divided 2400 by 80, so the answer to part (a) is exact
- Hot drinks are nicer than cold drinks, so more people will buy them
- The manager uses the results of 80 people for all 2400 people, so assumes the sample is representative.
- If it is not, the real difference could be bigger or smaller than 360.
Question 17Challenge3 marks
Two cafés ask some of their customers whether they would like oat milk.
At Café A, 18 customers say yes and 27 say no.
At Café B, 21 customers say yes and 39 say no.
What percentage of the customers asked at Café A said yes?
1 mark
What percentage of the customers asked at Café B said yes?
1 mark
Tom says, "Oat milk is more popular with Café B's customers, because more of them said yes." Is Tom right?
1 mark
Hint
Find how many were asked at each café before comparing.
Worked solution
Two cafés ask some of their customers whether they would like oat milk.
At Café A, 18 customers say yes and 27 say no.
At Café B, 21 customers say yes and 39 say no.
Part (a)
What percentage of the customers asked at Café A said yes?
- Café A asked 18+27=45 customers.
- 18\div45\times100=40\%
Part (b)
What percentage of the customers asked at Café B said yes?
- Café B asked 21+39=60 customers.
- 21\div60\times100=35\%
Part (c)
Tom says, "Oat milk is more popular with Café B's customers, because more of them said yes." Is Tom right?
- Yes, because 21 is more than 18
- No, because a greater proportion said yes at Café A
- No, because fewer customers were asked at Café B
- Yes, because Café B asked more customers
- More customers said yes at Café B, but Café B asked more customers.
- A greater proportion said yes at Café A, so Tom is wrong.
Question 18Challenge3 marks
A school surveys random samples from two year groups. Use the results to estimate the total number of pupils in these two years who travel by bus.
Hint
Make one estimate for each year, then combine them.
Worked solution
A school surveys random samples from two year groups. Use the results to estimate the total number of pupils in these two years who travel by bus.
- Year 8 estimate =12/40×360=108.
- Year 9 estimate =16/50×300=96.
- Combined estimate =108+96=204 pupils.
Question 19Challenge3 marks
A shop asks 80 randomly selected customers about a new product. Of these, 28 say they would buy it. The shop expects 1200 customers next week.
Use the survey to estimate the number who would buy the product.
2 marks
Sam works out 1200÷28×80 for part (a). Why is Sam’s method wrong?
1 mark
Hint
Check the direction of the proportion and whether the result is sensible.
Worked solution
A shop asks 80 randomly selected customers about a new product. Of these, 28 say they would buy it. The shop expects 1200 customers next week.
Part (a)
Use the survey to estimate the number who would buy the product.
- 28/80×1200=420 customers.
Part (b)
Sam works out 1200÷28×80 for part (a). Why is Sam’s method wrong?
- It uses the sample fraction the wrong way round and predicts more buyers than customers
- It gives a fraction, so it must be wrong
- A prediction always equals the sample size
- The fraction needed is 28/80, not 80/28. Sam’s calculation gives more than 1200 buyers, which is more than the number of customers expected.
Question 20Challenge4 marks
There are 3200 households in a town.
Ali and Bea want to find out how many of these households have solar panels.
Ali asks 40 households chosen at random. 9 of them have solar panels.
Bea asks 160 households chosen at random. 41 of them have solar panels.
Ali uses only his results and gets an estimate of 720 households. Bea uses only her results and gets an estimate of 820 households. Whose estimate is likely to be more reliable?
1 mark
Use all of the results to work out an estimate for the number of the 3200 households that have solar panels.
3 marks
Hint
Use both sets of results together, then scale up to the town.
Worked solution
There are 3200 households in a town.
Ali and Bea want to find out how many of these households have solar panels.
Ali asks 40 households chosen at random. 9 of them have solar panels.
Bea asks 160 households chosen at random. 41 of them have solar panels.
Part (a)
Ali uses only his results and gets an estimate of 720 households. Bea uses only her results and gets an estimate of 820 households. Whose estimate is likely to be more reliable?
- Ali's, because his estimate is smaller
- Bea's, because her estimate is bigger
- Bea's, because she asked more households than Ali
- Both are equally reliable, because both chose households at random
- Bea asked 160 households and Ali only 40.
- Results from more households are more reliable, so Bea's estimate is likely to be more reliable.
Part (b)
Use all of the results to work out an estimate for the number of the 3200 households that have solar panels.
- Households with solar panels: 9+41=50
- Households asked: 40+160=200
- \frac{50}{200}=\frac{1}{4}
- \frac{1}{4}\times3200=800 households.