Expanding Single Brackets
Question 11 mark
Expand 3(x+2).
Hint
Multiply both terms by the number outside.
Worked solution
Expand 3(x+2).
- 3\times x=3x and 3\times2=6.
- Therefore 3(x+2)=3x+6.
Question 21 mark
Expand 4(5+y).
Hint
The outside multiplier applies to both terms, whichever order they are written in.
Worked solution
Expand 4(5+y).
- 4\times5=20 and 4\times y=4y.
- The expansion is 20+4y, which can also be written 4y+20.
Question 31 mark
Expand 5(a-3).
Hint
Treat the second term inside as negative 3.
Worked solution
Expand 5(a-3).
- 5\times a=5a and 5\times(-3)=-15.
- The expansion is 5a-15.
Question 41 mark
Expand 2(3x+4).
Hint
Multiply the two coefficients in the first product.
Worked solution
Expand 2(3x+4).
- 2\times3x=6x and 2\times4=8.
- The expansion is 6x+8.
Question 52 marks
Expand x(x+6).
Hint
The same letter multiplied by itself gives a square.
Worked solution
Expand x(x+6).
- x\times x=x^2 and x\times6=6x.
- The expansion is x^2+6x. The powers are different, so the terms stay separate.
Question 62 marks
Expand 3a(2a+1).
Hint
Multiply the whole outside term by each inside term.
Worked solution
Expand 3a(2a+1).
- 3a\times2a=6a^2. Also, 3a\times1=3a.
- The expansion is 6a^2+3a.
Question 71 mark
Which option is the fully expanded form of -(x+7)?
Hint
A minus sign on its own means multiply every term by negative 1.
Worked solution
Which option is the fully expanded form of -(x+7)?
- -x+7
- x-7
- -x-7
- -(x+7)
- (-1)\times x=-x and (-1)\times7=-7.
- The expansion is -x-7. The option -(x+7) still contains the bracket, so it is not an expanded form.
Question 82 marks
Expand -3(4-t).
Hint
Keep the negative multiplier with each multiplication.
Worked solution
Expand -3(4-t).
- (-3)\times4=-12 and (-3)\times(-t)=3t.
- The expansion is -12+3t, or 3t-12.
Question 92 marks
Expand and simplify 2(x+3)+5.
Hint
Expand the bracket, then collect the constants.
Worked solution
Expand and simplify 2(x+3)+5.
- Expanding gives 2x+6+5.
- Collect the constants: 6+5=11. The answer is 2x+11.
Question 102 marks
Expand and simplify 4(x+2)+x.
Hint
After expanding, remember the x outside the bracket.
Worked solution
Expand and simplify 4(x+2)+x.
- Expanding gives 4x+8+x.
- Collect 4x+x=5x. The answer is 5x+8.
Question 112 marks
Expand and simplify 3(2y-4)-y.
Hint
Expand first, then combine the y terms with their signs.
Worked solution
Expand and simplify 3(2y-4)-y.
- The expansion is 6y-12-y.
- 6y-y=5y, so the answer is 5y-12.
Question 122 marks
Expand and simplify 2(p+5)+3(2-p).
Hint
Expand both brackets before collecting. The letter is the second term in one bracket.
Worked solution
Expand and simplify 2(p+5)+3(2-p).
- The two expansions are 2p+10 and 6-3p.
- Together: 2p+10+6-3p.
- The letter terms give 2p-3p=-p and the constants give 10+6=16, so the answer is 16-p.
Question 132 marks
Expand and simplify 5(a+1)-2(a+4).
Hint
Use negative 2 as the multiplier of the second bracket.
Worked solution
Expand and simplify 5(a+1)-2(a+4).
- The expression expands to 5a+5-2a-8.
- Collect: 5a-2a=3a and 5-8=-3. The answer is 3a-3.
Question 141 mark
Hana says 2(x+5)=2x+5. Write the correct expanded expression.
Hint
Check whether the outside multiplier has been applied to both terms.
Worked solution
Hana says 2(x+5)=2x+5. Write the correct expanded expression.
- The x term becomes 2x. The 5 must also be doubled, giving 10.
- The correct expansion is 2x+10. Hana multiplied only the first term.
Question 152 marks
The diagram shows a rectangle. All measurements are in centimetres.
Find a simplified expression for its perimeter.
Hint
There are two lengths and two widths.
Worked solution
The diagram shows a rectangle. All measurements are in centimetres.
Find a simplified expression for its perimeter.
- The perimeter is 2(2x+1)+2(x+4).
- Expanding gives 4x+2+2x+8. Collecting gives (6x+10) cm.
Question 16Challenge2 marks
Expand and simplify 3(2x-5)-2(x+4).
Hint
Include the subtraction sign in the second multiplier.
Worked solution
Expand and simplify 3(2x-5)-2(x+4).
- The first contribution is 6x-15. The second is -2x-8.
- Together: 6x-15-2x-8=4x-23.
Question 17Challenge3 marks
Expand and simplify -2x(3x-4)+5x.
Hint
The outside term includes a negative sign and an x.
Worked solution
Expand and simplify -2x(3x-4)+5x.
- The two products are (-2x)\times3x=-6x^2 and (-2x)\times(-4)=8x.
- Include the final 5x: -6x^2+8x+5x=-6x^2+13x.
Question 18Challenge3 marks
A rectangular corner is removed from a rectangular piece of card, as shown. All measurements are in centimetres.
Find an expanded, simplified expression for the area of the card remaining.
Hint
Find each rectangular area using one bracket, then subtract the removed area.
Worked solution
A rectangular corner is removed from a rectangular piece of card, as shown. All measurements are in centimetres.
Find an expanded, simplified expression for the area of the card remaining.
- The original area is 4(3x+2)=12x+8.
- The removed area is 2(x+1)=2x+2.
- Subtract all of the removed area: 12x+8-2x-2=10x+6. The remaining area is (10x+6)\text{ cm}^2.
Question 19Challenge3 marks
Here is an expression:
3(2x-3)+4(x+1)
Expand and simplify the expression.
2 marks
Work out the value of the expression when x=4.
1 mark
Hint
Multiply every term inside each bracket by the number outside it, then collect the x terms and the number terms.
Worked solution
Here is an expression:
3(2x-3)+4(x+1)
Part (a)
Expand and simplify the expression.
- 3(2x-3)=6x-9 and 4(x+1)=4x+4.
- Collect like terms: 6x+4x=10x and -9+4=-5, so the expression simplifies to 10x-5.
Part (b)
Work out the value of the expression when x=4.
- Use the simplified form: 10\times4-5=40-5=35.
- Check with the original: 3(8-3)+4(4+1)=15+20=35.
Question 20Challenge3 marks
Pack A contains (3n+4) stickers. Pack B contains (2n+4) stickers.
For any positive whole number n, how many more stickers are in 3 packs of B than in 2 packs of A?
Hint
Expand the two totals before comparing them; some terms will cancel.
Worked solution
Pack A contains (3n+4) stickers. Pack B contains (2n+4) stickers.
For any positive whole number n, how many more stickers are in 3 packs of B than in 2 packs of A?
- Two packs of A contain 2(3n+4)=6n+8 stickers.
- Three packs of B contain 3(2n+4)=6n+12 stickers.
- Both totals contain the same 6n. The difference is 12-8=4, so the three packs of B always contain 4 more stickers.