Estimation
Question 11 mark
Round 72 to one significant figure.
Hint
Keep the first non-zero digit and inspect the next digit.
Worked solution
Round 72 to one significant figure.
- 72 has 7 tens. The next digit is 2, so it rounds down to 70.
Question 21 mark
Round 0.086 to one significant figure.
Hint
The zeros before 8 are placeholders.
Worked solution
Round 0.086 to one significant figure.
- 8 is the first significant digit. The next digit is 6, so 0.086\approx0.09.
Question 32 marks
Estimate 29\times41 by rounding each number to one significant figure.
Hint
Round both inputs before multiplying.
Worked solution
Estimate 29\times41 by rounding each number to one significant figure.
- 29\approx30 and 41\approx40.
- 29\times41\approx30\times40=1200.
Question 42 marks
Estimate 583+216 by rounding each number to one significant figure.
Hint
Keep the hundreds place for both numbers.
Worked solution
Estimate 583+216 by rounding each number to one significant figure.
- 583\approx600 and 216\approx200.
- The estimated sum is 600+200=800.
Question 52 marks
Estimate 794-312 by rounding each number to one significant figure.
Hint
Round each number, then keep the subtraction.
Worked solution
Estimate 794-312 by rounding each number to one significant figure.
- 794\approx800 and 312\approx300.
- The estimated difference is 800-300=500.
Question 62 marks
Estimate 418\div5.2 by rounding each number to one significant figure.
Hint
Write the division using one-significant-figure values.
Worked solution
Estimate 418\div5.2 by rounding each number to one significant figure.
- 418\approx400 and 5.2\approx5.
- The estimate is 400\div5=80.
Question 72 marks
Estimate 7.7\times0.31 by rounding each number to one significant figure.
Hint
Keep the decimal place value when rounding 0.31.
Worked solution
Estimate 7.7\times0.31 by rounding each number to one significant figure.
- 7.7\approx8 and 0.31\approx0.3.
- The estimate is 8\times0.3=2.4.
Question 82 marks
Estimate 6.12\div0.29 by rounding each number to one significant figure.
Hint
How many tenths are in each rounded number?
Worked solution
Estimate 6.12\div0.29 by rounding each number to one significant figure.
- 6.12\approx6 and 0.29\approx0.3.
- 6\div0.3=60\div3=20.
Question 91 mark
Nia estimates 32\times48 by using 30\times50. Work out her estimate.
Hint
Multiply the rounded values that Nia uses.
Worked solution
Nia estimates 32\times48 by using 30\times50. Work out her estimate.
- 30\times50=1500.
- The original numbers were changed, so use \approx: 32\times48\approx1500.
Question 103 marks
Estimate \dfrac{39.2\times21.1}{8.3} by rounding each number to one significant figure.
Hint
Work out the rounded numerator before dividing.
Worked solution
Estimate \dfrac{39.2\times21.1}{8.3} by rounding each number to one significant figure.
- \dfrac{39.2\times21.1}{8.3}\approx\dfrac{40\times20}{8}.
- 40\times20=800, then 800\div8=100.
Question 112 marks
Nineteen identical folders cost £3.90 each. Estimate their total cost in pounds by rounding both numbers to one significant figure.
Hint
Estimate the number of folders and the price separately.
Worked solution
Nineteen identical folders cost £3.90 each. Estimate their total cost in pounds by rounding both numbers to one significant figure.
- 19\approx20 and 3.90\approx4.
- Estimated cost: 20\times4=80, or £80.
Question 123 marks
Estimate (47+23)\times3.8 by rounding each number to one significant figure.
Hint
Keep the brackets. Add inside them before multiplying.
Worked solution
Estimate (47+23)\times3.8 by rounding each number to one significant figure.
- The rounded calculation is (50+20)\times4.
- 50+20=70 and 70\times4=280.
Question 132 marks
A rectangular garden is 18.7 m long and 9.6 m wide. Estimate its area in square metres by rounding each length to one significant figure.
Hint
The area of a rectangle is length multiplied by width.
Worked solution
A rectangular garden is 18.7 m long and 9.6 m wide. Estimate its area in square metres by rounding each length to one significant figure.
- 18.7\approx20 m and 9.6\approx10 m.
- Estimated area: 20\times10=200 square metres.
Question 141 mark
After using a calculator to work out 6.14\div0.398, a student records 0.153. Which estimate best shows that this answer is unreasonable?
Hint
Round each original number to one significant figure without changing its place value.
Worked solution
After using a calculator to work out 6.14\div0.398, a student records 0.153. Which estimate best shows that this answer is unreasonable?
- 6\div0.4=15
- 6\div4=1.5
- 0.6\div0.4=1.5
- 6\div40=0.15
- 6.14\approx6 and 0.398\approx0.4.
- 6\div0.4=15, so the answer should be near 15, not near 0.15.
Question 151 mark
For 61\div3.9, Ravi uses the estimate 60\div4=15. Which statement is justified?
Hint
Consider the effect of changing 61 to 60, then separately consider changing 3.9 to 4.
Worked solution
For 61\div3.9, Ravi uses the estimate 60\div4=15. Which statement is justified?
- It is an overestimate because 4 is greater than 3.9.
- It is an underestimate because the amount being divided decreased and the number it is divided by increased.
- It is exact because both numbers were rounded.
- Its direction cannot be known without the exact answer.
- Changing 61 to 60 lowers the answer. Changing the number you divide by from 3.9 to 4 also lowers it.
- Both changes reduce the result, so 15 is an underestimate.
Question 16Challenge4 marks
A van uses 8.12 litres of fuel for every 100 km travelled. It makes a journey of 198 km. Fuel costs £1.98 per litre. Work out an estimate for the fuel cost of the journey, in pounds. Round 198, 8.12 and 1.98 to one significant figure.
Hint
Estimate the fuel used for the whole journey before finding its cost. The rate is given per 100 km.
Worked solution
A van uses 8.12 litres of fuel for every 100 km travelled. It makes a journey of 198 km. Fuel costs £1.98 per litre. Work out an estimate for the fuel cost of the journey, in pounds. Round 198, 8.12 and 1.98 to one significant figure.
- Round the journey distance to 200 km, the fuel consumption to 8 litres per 100 km, and the price to £2 per litre.
- The estimated fuel used is (200\div100)\times8=2\times8=16 litres. The 100 km reference in the rate stays unchanged.
- Estimated cost: 16\times2=32, or £32. This uses rounded inputs rather than rounding an exact final cost.
Question 17Challenge6 marks
A school orders 48 notebooks at £2.10 each and pays £19 delivery. Its budget is £120.
Round the number of notebooks, the price of one notebook and the delivery charge to one significant figure. Work out an estimate for the total cost in pounds.
3 marks
Using the exact prices, how many pounds are left from the budget?
3 marks
Hint
Use the stated rounding for the estimate. Then return to the original values for the budget decision.
Worked solution
A school orders 48 notebooks at £2.10 each and pays £19 delivery. Its budget is £120.
Part (a)
Round the number of notebooks, the price of one notebook and the delivery charge to one significant figure. Work out an estimate for the total cost in pounds.
- 48\approx50, 2.10\approx2 and 19\approx20.
- 50\times2+20=120, so the estimate is £120.
Part (b)
Using the exact prices, how many pounds are left from the budget?
- 48\times2.10+19=100.80+19=119.80.
- 120-119.80=0.20, so there is £0.20 left.
Question 18Challenge3 marks
A walker travels 11.8 km in 3.9 hours. Average speed is distance divided by time. The walker claims the average speed is at least 3 kilometres per hour.
Estimate the speed in kilometres per hour by rounding the distance and the time to the nearest whole number.
2 marks
Which conclusion is supported by a valid reason?
1 mark
Hint
Use the requested estimate first, then decide the claim using the original values.
Worked solution
A walker travels 11.8 km in 3.9 hours. Average speed is distance divided by time. The walker claims the average speed is at least 3 kilometres per hour.
Part (a)
Estimate the speed in kilometres per hour by rounding the distance and the time to the nearest whole number.
- 11.8\approx12 km and 3.9\approx4 hours.
- Estimated speed: 12\div4=3 kilometres per hour.
Part (b)
Which conclusion is supported by a valid reason?
- The claim is false: since 11.8 is less than 12, the exact speed must be less than 3 km/h.
- The claim is true: at 3 km/h, 3.9 hours gives 11.7 km, which is less than the distance travelled.
- The claim is true: an estimate of 3 km/h proves that the exact speed is at least 3 km/h.
- The claim is false: the exact speed is 3.9\div11.8, which is less than 3 km/h.
- At exactly 3 km/h, the distance in 3.9 hours would be 3\times3.9=11.7 km.
- The walker covers 11.8 km in that time, which is more than 11.7 km. The actual average speed is therefore above 3 km/h.
- The claim is true. The rough estimate alone was not accurate enough to settle it.
Question 19Challenge3 marks
Luca estimates 52\times19 using 50\times20=1000. By how much does his estimate exceed the exact value?
Hint
Work out the exact product and compare it with the stated estimate.
Worked solution
Luca estimates 52\times19 using 50\times20=1000. By how much does his estimate exceed the exact value?
- 52\times19=52\times(20-1)=1040-52=988.
- The difference is 1000-988=12, so the estimate exceeds the exact value by 12.
- One factor was rounded down and the other up. Those opposing changes alone do not establish the direction of the error; the comparison settles this case.
Question 20Challenge3 marks
A club needs 94 m of ribbon. Each roll contains 9.6 m. Priya estimates that 90\div10=9 rolls will be needed. Work out the fewest actual rolls the club must buy to have enough ribbon.
Hint
An estimate may not be enough to decide a purchase. Check how much ribbon whole rolls actually contain.
Worked solution
A club needs 94 m of ribbon. Each roll contains 9.6 m. Priya estimates that 90\div10=9 rolls will be needed. Work out the fewest actual rolls the club must buy to have enough ribbon.
- Nine rolls contain 9\times9.6=86.4 m, which is less than 94 m.
- Ten rolls contain 10\times9.6=96 m, which is enough. The fewest number of rolls is 10.
- The estimate reduced the required length and increased the length per roll, so it underestimated the number of rolls required.