Distance-Time Graphs
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How to read a journey from a distance-time graph, work out the speed for each part, spot the fastest part, complete a travel graph from a description and find the average speed for a whole journey.
Distance-time graphs in the exam
A distance-time graph, also called a travel graph, shows a journey. Time goes along the bottom. Distance from a starting place, such as home, goes up the side.
In the exam you are usually asked to read the graph: how far from home someone was at a certain time, or how many minutes they stopped for. These parts are worth 1 mark each.
You may also be asked to work out a speed from the graph, for 2 marks, or to complete the graph from a description of the rest of the journey, for 1 to 3 marks.
What the shape of the line tells you
- A line sloping up means moving away from home.
- A flat line means stopped: time passes, but the distance from home does not change.
- A line sloping down means coming back towards home. When it reaches 0 km, the person is home.
On this ride, the cyclist is 6 km from home at 09:30. The flat line runs from 09:30 to 10:30, so the stop lasts 1 hour. The cyclist is home again at 11:30.
Work out the scale first
Before you read anything, work out what one small square is worth on each axis. Count the small squares between two labels, then divide.
For example, if 1 hour is split into 6 small squares, each small square is 60\div6=10 minutes. If 4 km is split into 4 small squares, each small square is 1 km.
To read a value, draw a guideline with a ruler: from the axis to the line, then across or down to the other axis.
Times on the graph are clock times, and an hour has 60 minutes. From 10:45 to 11:20 is 15 minutes to 11:00, then 20 more, so 35 minutes.
Worked example 1: Reading a journey from the graph
Kai cycled from his home to a lake, stayed there for a while, then cycled home. The travel graph shows his journey.
(a) How far is the lake from Kai's home?
(b) For how many minutes did Kai stay at the lake?
- Work out the scales. Each hour is 6 small squares, so one small square is 10 minutes. Each 4 km is 4 small squares, so one small square is 1 km.
- The flat part is the stay at the lake. It is 2 small squares above 8 km, so the lake is 10 km from home.
- The flat part starts 4 small squares after 08:00, at 08:40, and ends 3 small squares after 09:00, at 09:30.
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Your turn. How many minutes is it from 08:40 to 09:30?
From 08:40 to 09:00 is 20 minutes, then 30 more to 09:30. That is 50 minutes.
- Answer: (a) 10 km (b) 50 minutes
Speed from a sloping line
The steepness of the line shows the speed. The speed is the gradient of the line: the distance it goes up or down for each hour along.
To work out the speed for one part of a journey, read the distance travelled and the time taken for that part. Then divide:
\text{speed}=\frac{\text{distance}}{\text{time}}
Distance in km and time in hours give a speed in km/h. Miles and hours give miles per hour (mph).
The distance travelled is how far the line goes up or down for that part, not where it ends. A part that goes from 20 km up to 35 km is 35-20=15 km travelled.
If the time is in minutes, scale up to 60 minutes. For example, 5 km in 20 minutes is 5\times3=15 km in 60 minutes, so the speed is 15 km/h. Dividing 5 by 20 gives kilometres per minute, not km/h.
Worked example 2: Speed for part of a journey
A delivery van left the depot at 08:00. The travel graph shows its journey. Work out the speed of the van, in km/h, for the first 20 minutes.
- Work out the scales. Each small square is 5 minutes across and 2 km up.
- From 08:00 to 08:20 the line goes up from 0 km to 14 km, which is 2 small squares above 10 km. So the van travels 14 km in 20 minutes.
- There are 60\div20=3 lots of 20 minutes in an hour.
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Your turn. How far would the van travel in 60 minutes at this speed?
14\times3=42, so 42 km in 60 minutes.
- Answer: 42 km/h
The steepest part is the fastest
Compare the parts of a journey by how steep they are. The steeper the line, the faster the journey. A flat line has a speed of 0
On the bike ride above, going away covers 6 km in 30 minutes, which is 12 km/h. Coming back covers 6 km in 1 hour, which is 6 km/h. The going-away line is the steeper one.
A line sloping down can be the steepest part too. Sloping down only means the direction is towards home; it does not mean slower.
Worked example 3: Finding the fastest part
Grace drove from her home to a garden centre and back. Her travel graph has four parts, labelled A, B, C and D. On which part was Grace driving fastest? Work out her speed on that part, in km/h.
- Part C is flat, so Grace was stopped. Parts A, B and D are moving.
- Part B is the steepest line, so it is the fastest part.
- On part B, Grace goes from 30 km to 60 km, which is 30 km, between 09:00 and 09:30, which is 30 minutes.
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Your turn. Work out Grace's speed on part B, in km/h.
30 km in half an hour is 30\times2=60 km in 1 hour.
- Check the others. Part A: 30 km in 1 hour is 30 km/h. Part D: 60 km in 1.5 hours is 60\div1.5=40 km/h. Both are slower.
- Answer: part B, at 60 km/h
Drawing the rest of a journey
Some questions describe the rest of a journey and ask you to complete the graph. Start each new part where the last part ends.
- For a stop, draw a flat line for the length of the stop.
- For a part at a steady speed, work out where it ends, then join the two points with a ruled straight line.
- For a journey home, the line must end on the time axis, at 0 km.
To find where a part ends, use one of these:
\text{distance}=\text{speed}\times\text{time}
\text{time}=\frac{\text{distance}}{\text{speed}}
For example, at 40 km/h for 30 minutes, which is half an hour, a car travels 40\div2=20 km.
Then turn the time into small squares. On a grid where each small square is 5 minutes, 20 minutes is 20\div5=4 small squares.
Worked example 4: Completing a travel graph
Leah cycled from her home to a market 12 km away. The travel graph shows her journey to the market. She stayed at the market for 30 minutes. She then cycled home at a steady speed of 18 km/h. Complete the travel graph. At what time did Leah get home?
- Each small square is 5 minutes across and 1 km up. Leah reached the market, 12 km from home, at 09:45.
- She stayed 30 minutes, until 10:15. Draw a flat line at 12 km from 09:45 to 10:15, which is 6 small squares.
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Your turn. How many minutes did Leah take to cycle the 12 km home at 18 km/h?
At 18 km/h she cycles 6 km every 20 minutes, so 12 km takes 40 minutes.
- She left the market at 10:15, so she got home 40 minutes later, at 10:55. Draw a straight line from 12 km at 10:15 down to 0 km at 10:55.
- Answer: Leah got home at 10:55.
Average speed for a whole journey
The average speed for a whole journey uses the total distance travelled and the total time, including any stops:
\text{average speed}=\frac{\text{total distance}}{\text{total time}}
For a journey there and back, the total distance is there and back. A walk of 5 km to a shop and 5 km home is 10 km, even though the graph ends at 0 km from home.
Read the total time from the start of the graph to the end. A stop adds time but no distance, so it makes the average speed lower.
Worked example 5: Average speed there and back
Ravi cycled from his home to a castle, stopped there, then cycled home. The travel graph shows his journey. Work out Ravi's average speed, in km/h, for the whole journey, including the stop.
- Each small square is 15 minutes across and 1 km up. The flat part is at 15 km, so the castle is 15 km from home.
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Your turn. What is the total distance Ravi cycled, in km?
15 km there and 15 km back is 15+15=30 km.
- He left at 09:00 and was home at 12:00, so the total time is 3 hours. This includes the 45 minute stop.
- Average speed: 30\div3=10
- Answer: 10 km/h
Worked example 6: Reading a sloping part of the graph
Mia cycled from her home to a farm. She stayed at the farm, then walked home, pushing her bike. The travel graph shows her journey.
(a) How far from home was Mia at 11:50?
(b) How far had Mia travelled altogether by 11:50?
- Each small square is 10 minutes across and 1 km up. The flat part is at 8 km, so the farm is 8 km from home.
- At 11:50 Mia is on the sloping line coming home. 11:50 is 1 small square before 12:00. Draw a guideline up from 11:50 to the line, then across to the distance axis.
- The guideline meets the distance axis 1 small square above 4 km. So at 11:50 Mia was 5 km from home.
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Your turn. Mia walked from 8 km from home to 5 km from home. How many km had she walked?
8-5=3, so she had walked 3 km back towards home.
- Distance travelled never goes down. Mia cycled 8 km to the farm, then walked 3 km back, so 8+3=11 km
- Answer: (a) 5 km (b) 11 km
Common mistakes
- Misreading the scale. Count the small squares between two labels first; on a 10-minute scale, one small square is not 1 minute.
- Dividing time by distance. Speed is distance divided by time, so 6 km in 2 hours is 6\div2=3 km/h.
- Dividing by the minutes for a speed in km/h. Scale up to 60 minutes: 6 km in 20 minutes is 18 km/h, not 0.3
- Using 100 minutes in an hour. An hour has 60 minutes, so 45 minutes is 0.75 hours, not 0.45 hours.
- Using where the line ends instead of how far it goes. For one part, subtract: from 20 km to 35 km is 15 km travelled.
- Leaving out the stop or the way back in an average speed. Use the total distance there and back, and the total time including stops.
More on this topic: Distance-Time Graphs worksheet with full solutions