Factorising
How to take out common factors, factorise quadratics and differences of squares, and recognise a repeated bracket.
Factorising reverses expanding
Factorising writes a sum or difference as a product. Always look for a common numerical or algebraic factor first. Fully factorised means that no remaining factor can be broken down further in the required number system.
For a common letter factor, take the lowest power present in every term. Check your answer by expanding it.
Worked example 1
Factorise fully 18x^3y^2-12x^2y^3
- The highest common numerical factor is 6. Both terms contain x^2y^2, so take out 6x^2y^2
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Your turn. Divide 18x^3y^2 by 6x^2y^2. What remains?
The first term inside the bracket is 3x
- Answer: 6x^2y^2(3x-2y). The second term inside the bracket is -2y
Find two numbers with the right sum and product
To factorise x^2+bx+c, find two numbers with sum b and product c. If the product is negative, their signs are opposite. If the product is positive, their signs agree.
Worked example 2
Factorise x^2+x-20
- We need a product of -20 and a sum of 1. The numbers are 5 and -4
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Your turn. Check the sum 5+(-4)
5+(-4)=1
- Answer: (x+5)(x-4). The cross terms are 5x-4x=x
Explore factors and roots
Try it: a factor (x-p) gives a root x=p. If the factor is (x+2), the root is -2, not 2. Factorising an expression and solving an equation are different tasks.
Split the middle term
For ax^2+bx+c, find two numbers with product ac and sum b. Split bx using those numbers, then factorise in pairs. The common bracket is a useful check.
Worked example 3
Factorise 6x^2-x-12
- The product is 6(-12)=-72 and the sum is -1. Use 8 and -9
- Split and group: 6x^2+8x-9x-12=2x(3x+4)-3(3x+4)
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Your turn. What is the common bracket?
The common bracket is 3x+4
- Answer: (3x+4)(2x-3)
Worked example 4
Factorise 4a^2-13ab+3b^2
- Treat this as a quadratic in a. Split -13ab as -12ab-ab because (-12)(-1)=12
- Group: 4a(a-3b)-b(a-3b)
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Your turn. After taking out (a-3b), what other factor remains?
The other factor is 4a-b
- Answer: (a-3b)(4a-b)
Look for a difference of squares or a repeated bracket
u^2-v^2=(u-v)(u+v)
This needs a subtraction: a sum of two squares does not factorise this way over the reals. After one factorisation, check whether a factor can be factorised again.
A common factor can be a whole bracket. Keep that bracket together while working out what remains.
Worked example 5
Factorise fully over the integers 3x^4-48
- Take out 3: 3(x^4-16). Then use a difference of squares: 3(x^2-4)(x^2+4)
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Your turn. Factorise x^2-4
x^2-4=(x-2)(x+2)
- Answer: 3(x-2)(x+2)(x^2+4). The last factor does not factorise further over the integers.
Worked example 6
Factorise fully 2x(x-3)+5(x-3)-(x-3)^2
- Each term contains (x-3). Taking it out gives (x-3)\bigl(2x+5-(x-3)\bigr)
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Your turn. Simplify 2x+5-(x-3)
2x+5-x+3=x+8
- Answer: (x-3)(x+8). The subtraction changes both signs inside the inner bracket.
Common mistakes
- Leaving a common factor behind. Take out the highest common factor first.
- Checking the product but not the sum. Your chosen pair must satisfy both conditions.
- Losing signs when taking out a negative. Divide every term by the negative factor, then expand to check.
- Stopping too early. Check whether any factor can be factorised further.
- Giving roots instead of factors. For “factorise”, leave the answer as a product.
Now try it: Factorising practice questions
More on this topic: Factorising worksheet with full solutions